Solution #2baa50c1-9c81-46b8-8af0-08d964c9e270
completedScore
80% (4/5)
Runtime
57μs
Delta
No change vs parent
-20.0% vs best
Same as parent
Score
80% (4/5)
Runtime
57μs
Delta
No change vs parent
-20.0% vs best
Same as parent
def solve(input):
jobs = input.get("jobs", []) if isinstance(input, dict) else []
if not jobs:
return 0
def build(i, acc):
if i >= len(jobs):
return acc
job = jobs[i]
if isinstance(job, (list, tuple)) and len(job) == 3:
return build(i + 1, acc + [tuple(job)])
return build(i + 1, acc)
arr = build(0, [])
if not arr:
return 0
def merge(a, b, key):
if not a:
return b
if not b:
return a
if key(a[0]) <= key(b[0]):
return [a[0]] + merge(a[1:], b, key)
return [b[0]] + merge(a, b[1:], key)
def mergesort(a, key):
n = len(a)
if n <= 1:
return a
mid = n // 2
return merge(mergesort(a[:mid], key), mergesort(a[mid:], key), key)
arr = mergesort(arr, lambda x: x[0])
n = len(arr)
starts = list(map(lambda x: x[0], arr))
def lower_bound(x, lo, hi):
if lo >= hi:
return lo
mid = (lo + hi) // 2
if starts[mid] < x:
return lower_bound(x, mid + 1, hi)
return lower_bound(x, lo, mid)
memo = {}
def dp(i):
if i >= n:
return 0
if i in memo:
return memo[i]
s, e, w = arr[i]
j = lower_bound(e, i + 1, n)
take = w + dp(j)
skip = dp(i + 1)
memo[i] = take if take > skip else skip
return memo[i]
return dp(0)Score Difference
-20.0%
Runtime Advantage
39μs slower
Code Size
61 vs 39 lines
| # | Your Solution | # | Champion |
|---|---|---|---|
| 1 | def solve(input): | 1 | def solve(input): |
| 2 | jobs = input.get("jobs", []) if isinstance(input, dict) else [] | 2 | if not isinstance(input, dict): |
| 3 | if not jobs: | 3 | return 0 |
| 4 | return 0 | 4 | raw = input.get("jobs") |
| 5 | 5 | if not raw: | |
| 6 | def build(i, acc): | 6 | return 0 |
| 7 | if i >= len(jobs): | 7 | |
| 8 | return acc | 8 | jobs = [] |
| 9 | job = jobs[i] | 9 | for j in raw: |
| 10 | if isinstance(job, (list, tuple)) and len(job) == 3: | 10 | if isinstance(j, (list, tuple)) and len(j) == 3: |
| 11 | return build(i + 1, acc + [tuple(job)]) | 11 | jobs.append((j[1], j[0], j[2])) # sort by end, store as (end, start, weight) |
| 12 | return build(i + 1, acc) | 12 | if not jobs: |
| 13 | 13 | return 0 | |
| 14 | arr = build(0, []) | 14 | |
| 15 | if not arr: | 15 | jobs.sort() |
| 16 | return 0 | 16 | ends = [] |
| 17 | 17 | bests = [] | |
| 18 | def merge(a, b, key): | 18 | |
| 19 | if not a: | 19 | for e, s, w in jobs: |
| 20 | return b | 20 | lo = 0 |
| 21 | if not b: | 21 | hi = len(ends) |
| 22 | return a | 22 | while lo < hi: |
| 23 | if key(a[0]) <= key(b[0]): | 23 | mid = (lo + hi) >> 1 |
| 24 | return [a[0]] + merge(a[1:], b, key) | 24 | if ends[mid] <= s: |
| 25 | return [b[0]] + merge(a, b[1:], key) | 25 | lo = mid + 1 |
| 26 | 26 | else: | |
| 27 | def mergesort(a, key): | 27 | hi = mid |
| 28 | n = len(a) | 28 | |
| 29 | if n <= 1: | 29 | candidate = w + (bests[lo - 1] if lo else 0) |
| 30 | return a | 30 | current = bests[-1] if bests else 0 |
| 31 | mid = n // 2 | 31 | |
| 32 | return merge(mergesort(a[:mid], key), mergesort(a[mid:], key), key) | 32 | if candidate > current: |
| 33 | 33 | if ends and ends[-1] == e: | |
| 34 | arr = mergesort(arr, lambda x: x[0]) | 34 | bests[-1] = candidate |
| 35 | n = len(arr) | 35 | else: |
| 36 | 36 | ends.append(e) | |
| 37 | starts = list(map(lambda x: x[0], arr)) | 37 | bests.append(candidate) |
| 38 | 38 | ||
| 39 | def lower_bound(x, lo, hi): | 39 | return bests[-1] if bests else 0 |
| 40 | if lo >= hi: | 40 | |
| 41 | return lo | 41 | |
| 42 | mid = (lo + hi) // 2 | 42 | |
| 43 | if starts[mid] < x: | 43 | |
| 44 | return lower_bound(x, mid + 1, hi) | 44 | |
| 45 | return lower_bound(x, lo, mid) | 45 | |
| 46 | 46 | ||
| 47 | memo = {} | 47 | |
| 48 | 48 | ||
| 49 | def dp(i): | 49 | |
| 50 | if i >= n: | 50 | |
| 51 | return 0 | 51 | |
| 52 | if i in memo: | 52 | |
| 53 | return memo[i] | 53 | |
| 54 | s, e, w = arr[i] | 54 | |
| 55 | j = lower_bound(e, i + 1, n) | 55 | |
| 56 | take = w + dp(j) | 56 | |
| 57 | skip = dp(i + 1) | 57 | |
| 58 | memo[i] = take if take > skip else skip | 58 | |
| 59 | return memo[i] | 59 | |
| 60 | 60 | ||
| 61 | return dp(0) | 61 |
1def solve(input):2 jobs = input.get("jobs", []) if isinstance(input, dict) else []3 if not jobs:4 return 056 def build(i, acc):7 if i >= len(jobs):8 return acc9 job = jobs[i]10 if isinstance(job, (list, tuple)) and len(job) == 3:11 return build(i + 1, acc + [tuple(job)])12 return build(i + 1, acc)1314 arr = build(0, [])15 if not arr:16 return 01718 def merge(a, b, key):19 if not a:20 return b21 if not b:22 return a23 if key(a[0]) <= key(b[0]):24 return [a[0]] + merge(a[1:], b, key)25 return [b[0]] + merge(a, b[1:], key)2627 def mergesort(a, key):28 n = len(a)29 if n <= 1:30 return a31 mid = n // 232 return merge(mergesort(a[:mid], key), mergesort(a[mid:], key), key)3334 arr = mergesort(arr, lambda x: x[0])35 n = len(arr)3637 starts = list(map(lambda x: x[0], arr))3839 def lower_bound(x, lo, hi):40 if lo >= hi:41 return lo42 mid = (lo + hi) // 243 if starts[mid] < x:44 return lower_bound(x, mid + 1, hi)45 return lower_bound(x, lo, mid)4647 memo = {}4849 def dp(i):50 if i >= n:51 return 052 if i in memo:53 return memo[i]54 s, e, w = arr[i]55 j = lower_bound(e, i + 1, n)56 take = w + dp(j)57 skip = dp(i + 1)58 memo[i] = take if take > skip else skip59 return memo[i]6061 return dp(0)1def solve(input):2 if not isinstance(input, dict):3 return 04 raw = input.get("jobs")5 if not raw:6 return 078 jobs = []9 for j in raw:10 if isinstance(j, (list, tuple)) and len(j) == 3:11 jobs.append((j[1], j[0], j[2])) # sort by end, store as (end, start, weight)12 if not jobs:13 return 01415 jobs.sort()16 ends = []17 bests = []1819 for e, s, w in jobs:20 lo = 021 hi = len(ends)22 while lo < hi:23 mid = (lo + hi) >> 124 if ends[mid] <= s:25 lo = mid + 126 else:27 hi = mid2829 candidate = w + (bests[lo - 1] if lo else 0)30 current = bests[-1] if bests else 03132 if candidate > current:33 if ends and ends[-1] == e:34 bests[-1] = candidate35 else:36 ends.append(e)37 bests.append(candidate)3839 return bests[-1] if bests else 0