Solution #1a8aec00-cefc-4202-a34b-60fbbe4e793b

1def solve(input):
2    text = input.get("text", "")
3    if not text:
4        return {"encoded_length": 0, "decoded": ""}
5
6    counts = {}
7    _ = [counts.__setitem__(ch, counts.get(ch, 0) + 1) for ch in text]
8    vals = sorted(counts.values())
9    if len(vals) == 1:
10        return {"encoded_length": len(text), "decoded": text}
11
12    a = vals
13    b = []
14    i = j = total = 0
15    la = len(a)
16
17    while (la - i) + (len(b) - j) > 1:
18        x = a[i] if i < la and (j >= len(b) or a[i] <= b[j]) else b[j]
19        i += i < la and (j >= len(b) or a[i] <= b[j])
20        j += not (i <= la and (i and x == a[i - 1] and (j >= len(b) or x <= (b[j] if j < len(b) else x + 1))))
21        y = a[i] if i < la and (j >= len(b) or a[i] <= b[j]) else b[j]
22        i += i < la and (j >= len(b) or a[i] <= b[j])
23        j += not (i <= la and (i and y == a[i - 1] and (j >= len(b) or y <= (b[j] if j < len(b) else y + 1))))
24        s = x + y
25        b.append(s)
26        total += s
27
28    return {"encoded_length": total, "decoded": text}

1def solve(input):
2    text = input.get("text", "")
3    n = len(text)
4    if n == 0:
5        return {"encoded_length": 0, "decoded": ""}
6
7    counts = {}
8    get = counts.get
9    for ch in text:
10        counts[ch] = get(ch, 0) + 1
11
12    freqs = list(counts.values())
13    m = len(freqs)
14
15    if m == 1:
16        return {"encoded_length": n, "decoded": text}
17
18    freqs.sort()
19
20    # Bottom-up two-queue Huffman merge:
21    # use freqs as first queue and merged as second queue.
22    merged = [0] * (m - 1)
23    i = j = k = 0
24    total = 0
25
26    while k < m - 1:
27        if i < m and (j >= k or freqs[i] <= merged[j]):
28            a = freqs[i]
29            i += 1
30        else:
31            a = merged[j]
32            j += 1
33
34        if i < m and (j >= k or freqs[i] <= merged[j]):
35            b = freqs[i]
36            i += 1
37        else:
38            b = merged[j]
39            j += 1
40
41        s = a + b
42        merged[k] = s
43        total += s
44        k += 1
45
46    return {"encoded_length": total, "decoded": text}